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Topic: Novel formation of MB2  (Read 1537 times)

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Offline kimphys1

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Novel formation of MB2
« on: February 09, 2024, 10:27:17 AM »
I'm running some experiments on forming a transition metal diboride (MB2) layer on a lanthanum hexaboride base. My education background is in Physics with some basic Chemistry, so I'm in a little over my head here. I'm looking for some help in determining if the reaction will be favorable and at what temperatures. So far I have found that the details will be most likely be determined by the Gibbs Free Energy equation, ΔG=ΔH-TΔS. I found some values for these variables, but also found it a bit confusing. I'm not entirely sure of which transition metal (M) I will be using yet, but have narrowed it down to most likely either Ti or Zr. The reaction that I'm trying to determine the details of is LaB6+M=LaB4+MB2. The general idea is that I will coat the LaB6 base with a thin layer of the M, and then heat to form a thin MB2 layer with a then boron depleted layer of LaB4 underneath. Any help that can be provided will be useful. Thank you!

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