[antonioro00071]

The Ph of a solution obtained through the solubilisation at 22°C of 0,365 g HCl, 0,585 g NaCl and 0,70 g NH₄OH with water at a final volume of 100 ml (К_NH4OH = 1,7×10^-5; Kw = 10^-14) is:


What I did: Obtained the molar concentration of the HCl, NaCl and NH₄OH, I calculated how much NH₄OH was left after reacting with HCl. I dont know how to calculate the final pH using the constants.

[Hunter2]

Hint: Henderson Hasselbalch  equation.

[antonioro00071]

Hint: Henderson Hasselbalch  equation.

Thank you a lot, now I have figured this out!