The BP of CCl4 is 170.1 F, and that for CHCl3 is 142.2 F, which would contradict what would otherwise be expected. While there is a dipole with CHCl3, it's force of attraction is not > than the overall LDF tied to the extra Cl in CCl4. The extra electrons tied to the extra Cl, relative to what you'd have from H, is enough for the LDFs of CCl4 to beat out the effect of the dipole tied to CHCl3.