[qumhh]

Sorry, i'm new to doing chemical reactions in the lab format. Can someone please explain this calculation? Not sure how much to add of each to reach the equivalents provided. Can someone please run me through this at a ground level so i could do this reaction in lab? Thanks!"To a solution of epoxide with 10 carbon tails (C10) (1,2-epoxydodecane; Sigma-Aldrich), piperazine- and piperidine-containing amines were added at a ratio of 1.2*N:1 epoxide/amine, where N is the number of secondary amine*1 + number of primary amine*2. For example, to synthesize 246C10, to a 5-ml vial, 1 ml of epoxide (4.65 mmol, 4.8 equivalents) was added and 200 μl of amine (0.97 mmol, 1 equivalent) was added dropwise."

[Hunter2]

Not much information.
What is 246C10 ? This one

https://www.caymanchem.com/product/37907

Piperazine and Piperidin are secondary Amins. I don't see any primary  amins.
The formula 1.2*N:1 epoxide/amine means what?

The mole ratio 4,65 mmol Epoxy with 0,97 mmol Amin is the ration 4,8:1 equivalents.
What is the real Amin reactant? According the link it has to be N,N'-bis (1-aminoprop-3-yl)-piperazin.
Which has primary Amine and tertiary  Amin groups.
According the formula if N = 4 it fulfills (1.2*4):1 =4.8:1 what means we need 4 Epoxy and 1 Amin reactant.