[rentj]

In a single metal displacement, the more reactive metal would displace the less-reactive metal (in an ionic compound). Let A and B be metals while C be non-metal, where A is more reactive than B. The single displacement model will be like this:
A + BC --> AB + C

What if metal A has more than common oxidation states, like Fe? What will the product be?
Fe + CuCl2 --> FeCl2 + Cu
OR
Fe + CuCl2 --> FeCl3 + Cu

Thank you.

[Borek]

The only way to predict is to check redox potentials in tables to see where the oxidation stops (or if it will even start).

[Corribus]

Second option is not a balanced equation, so that's also something to consider.

[floatsguil]

Under standard conditions, the more likely product of the reaction between iron (Fe) and copper(II) chloride (CuCl₂) is FeCl₂ (iron(II) chloride), with iron in the +2 oxidation state:

Fe + CuCl₂ → FeCl₂ + Cu
However, under specific conditions (e.g., high temperature or a strong oxidizing environment), it’s possible to form FeCl₃ (iron(III) chloride) with iron in the +3 oxidation state:

Fe + CuCl₂ → FeCl₃ + Cu
So, the actual product depends on the reaction conditions space waves 

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