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Topic: Number of d electrons  (Read 5127 times)

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Offline lord12

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Number of d electrons
« on: December 05, 2006, 06:59:11 PM »
I can't quite figure out the number of d electrons in [Au(CO)4]3-. I looked it up and there are 8 d electrons. But I want to onown the reasoning.
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Offline Yggdrasil

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Re: Number of d electrons
« Reply #1 on: December 05, 2006, 07:13:19 PM »
If you know the charge of the ligands and the charge of the complex, you can figure out the charge of the metal ion.  From the charge of the metal ion and its atomic number, you can figure out how many electons it has.
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Offline swati

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Re: Number of d electrons
« Reply #2 on: December 06, 2006, 03:28:46 PM »
In this case carbonyl that is CO is a neutral ligand, so calculate the charge on ligand
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Offline mdlhvn

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Re: Number of d electrons
« Reply #3 on: December 08, 2006, 12:20:03 AM »
Quote from: lord12 on December 05, 2006, 06:59:11 PM
I can't quite figure out the number of d electrons in [Au(CO)4]3-. I looked it up and there are 8 d electrons. But I want to onown the reasoning.

Maybe you confuse the fomula. It must be [Au(CO)4]+ or [Au(CO)4]3+. I think 3+ is more suitable. Because CO is the neutral ligand, the charge of the complex is equal to that of metal ion. The electron configuration of Au is 5d106s1, so Au3+ must have 8 d electrons

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