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Topic: empirical formulas  (Read 8587 times)

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Offline stars_below

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empirical formulas
« on: October 29, 2006, 03:32:54 PM »
A 4.628-g sample of an iron oxide was found to contain 3.348 g of iron and 1.280 g of oxygen. What is the simplest formula for this compound?

i solved up to the point of having FeO1.3 but i don't know what to do next, can anyone help

Offline Albert

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Re: empirical formulas
« Reply #1 on: October 29, 2006, 03:47:03 PM »
Certainly a chemical formula should contain integers only. I believe you solved the problem correctly: you simply forgot that, in this case, you always have to approximate to the closest integer (but perhaps it's not your fault: no one has ever told you it).

Hence, I bet the answer is just FeO.

Offline Borek

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Re: empirical formulas
« Reply #2 on: October 29, 2006, 04:01:54 PM »
Check if Fe3O4 doesn't fit better ;)
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Re: empirical formulas
« Reply #3 on: October 29, 2006, 04:14:07 PM »
Fe3O4 is the answer that im suppose to get, but i don't know how to figure it out, am i suppose to do something with the 4.628g?

Offline enahs

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Re: empirical formulas
« Reply #4 on: October 29, 2006, 04:24:59 PM »
You have 0.059 mol of Iron and 0.040 mol of O.

That means you have

0.059 mol Fe
0.080 mol O

Or in English and doing the math that ratio means you have 1.35 mol of O per 1 mol of Fe.
You need whole numbers, so what is the smallest whole number you need to multiply by to get that 1.35 to be a integer? By 3, which 1.35 * 3 = 4.05 which is ~4. Now you must also be fair mathematically and multiply the Fe times 3 as well. After that is all done you have Fe3O4.

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