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Topic: Molar concentration (Read 4462 times)
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benn121
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Molar concentration
«
on:
November 01, 2006, 05:18:47 AM »
Hi guys, I feel cheeky asking for help but im doing a civil engineering phd and i have to do an element of chemistry in it. The problem is i have to answer a few questions to put in my thesis as regards to checmistry. I have done all of them except this one,
Calcaulate the molar concentration of hydroxyl ions (OH-) when 260 mg of potassium hydroxide (KOH) are dissolved in 0.5 litres of pure water and hence find the pH of this alkaline.
I have researched how to find the molar concentration and I have come up with an equation CX = NX / Vsoh
Is this right? can anyone offer any help or advice?
Thank you if you can
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Albert
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Re: Molar concentration
«
Reply #1 on:
November 01, 2006, 05:58:15 AM »
First, you have to convert mg into moles by dividing the weight by the molecular weight of potassium hydroxide.
Then, you calculate the molarity of hydroxyl ions: moles/Volume. Once here, you calculate the pOH (-log molarity of OH
-
).
pH = 14- pOH
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benn121
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Re: Molar concentration
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Reply #2 on:
November 01, 2006, 06:06:50 AM »
That is brilliant thank you very much for your help
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