Also, no rush? It says it is due tomorrow, fyi.
ya, have you tried it?
I'll help you with one of them...
The spectroscopy problem at the bottom..
1.) Find the degrees of unsat... I got 6
3.) The IR peak at 1725, what is that characteristic of? a Carbonyl C=O stretch
So that is 1 deg of unsat, 5 more to find...
in the NMR 4H multiplet at 7.2-7.7 ppm.. What region is this... I think it is the aromatic region. Now that takes care of 4 deg of unsat, you gotta find one more...
Also, if you have a 4H signal in the benzene region, that means your benzene is disubstituted so now you should figure out if it is para ortho or meta substituted....
Here is a link to a page on my teachers website with some useful chemical shifts that you might want to see
http://www.asu.edu/courses/chm331/notes/spect/S12.htmlHope that helped.. let me know if your still confused