[funboy]

to make 1.0 mol/L of a solution, do you:

take the molecular weight of the substance (ie HCl 36.5 g) add that to a 1 litre container and then top up with water until 1 litre is displaced??

If you are working with a dilute substance (muriatic acid only 31.5% HCl), if you took 100ml of the solution that would give you 31.5ml of HCl then add 900 ml of water and this gives you CLOSE to 1 mol/L

If I use vinegar to make 1.0mol/L of acetic acid??
vinegar only has 5-18% acetic acid, but the molecular weight of acetic acid is 60.05g, so would I have to use 330ml of vinegar to 670ml of water to get 1.0mol/L of acetic acid??

Trying to make a bunch of solutions for an experiment and want to make sure they are correct

[Borek]

to make 1.0 mol/L of a solution, do you:

take the molecular weight of the substance (ie HCl 36.5 g) add that to a 1 litre container and then top up with water until 1 litre is displaced??

OK. Although you better start with some water, add acid to it, stirr, then fill up to the mark.

If you are working with a dilute substance (muriatic acid only 31.5% HCl), if you took 100ml of the solution that would give you 31.5ml of HCl then add 900 ml of water and this gives you CLOSE to 1 mol/L

31.5% of 100 mL will give 31.5 mL only if it is %v/v. HCl is most likely w/w.

Check concentration lectures. CASC will help you too, IIRC you've bought it few months ago

If I use vinegar to make 1.0mol/L of acetic acid??
vinegar only has 5-18% acetic acid, but the molecular weight of acetic acid is 60.05g, so would I have to use 330ml of vinegar to 670ml of water to get 1.0mol/L of acetic acid??

No idea what you are referring to. Please show your calculations.

[funboy]

where I was going with the vinegar

assuming its 18%

100 ml vinegar = 18ml acetic acid

60/18 = 3.33

3.33 X 100ml = 333 ml of vinegar to get 1 mol of acetic acid

turns out that my vinegar at home was only 5% acetic acid, I dont know how to get 1 mol/L when it would take 1200ml of vinegar to get one mole acetic acid.

[Borek]

where I was going with the vinegar

assuming its 18%

100 ml vinegar = 18ml acetic acid

Assuming it is v/v%. Which it probably is not.

60/18 = 3.33

Only if the density of pure acetic acid is 1 g/mL. It is more like 1.05 g/mL.

3.33 X 100ml = 333 ml of vinegar to get 1 mol of acetic acid

325mL of 18% w/w if you take density changes into account. Please remember that when mixing liquids sum of volumes is only rarely exactly equal to the final volume.

turns out that my vinegar at home was only 5% acetic acid, I dont know how to get 1 mol/L when it would take 1200ml of vinegar to get one mole acetic acid.

1M acetic acid is almost 6% w/w, you can't prepare it using less concentrated solution.

Play with CASC, it was written just to help in such calculations.