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Topic: Rate Laws  (Read 3723 times)

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Offline soccer05

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Rate Laws
« on: January 15, 2007, 03:16:18 PM »
i don't understand this problem i have:

A reaction that is 2nd order in one reactant has a rate constant of 1.0 x 10^-2 M/s. If the initial concentration of the reactant is 1.00 M, how long will it take for the concentration go become 0.0476 M?
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Offline soccer05

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Re: Rate Laws
« Reply #1 on: January 15, 2007, 03:18:32 PM »
The possiblities are:

a) 100 s
b) 500 s
c) 1000 s
d) 2000 s
e) 5000 s


I am leaning towards a) because the rate should be the change in concentration divided by the change in time, but I am not sure whether I am on the right track.
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Offline Yggdrasil

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Re: Rate Laws
« Reply #2 on: January 15, 2007, 03:24:01 PM »
What is the integrated rate law for a second-order reaction?
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Offline thegame11

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Re: Rate Laws
« Reply #3 on: January 15, 2007, 07:05:38 PM »
Quote from: soccer05 on January 15, 2007, 03:16:18 PM
i don't understand this problem i have:

A reaction that is 2nd order in one reactant has a rate constant of 1.0 x 10^-2 M/s. If the initial concentration of the reactant is 1.00 M, how long will it take for the concentration go become 0.0476 M?

How can the units of rate constant of second law be in M/s.  I think the units should be in 1/(M s).  Do a dimensional analysis.
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