Hi,
The reaction 2SO2 + O2 <---> 2SO3 is made to place at t C in a closed vessel of 1 litre capacity and allowed to attain equilibrium.The equilibrium mixture contains 48g SO3, 12.8g SO2 and 9.6g of O2. Determince Kc.
My work:
2SO2 + O2 <---> 2SO3
12.8/64 M 9.6/32 M 48/80 M
Kc = (48/80)^2 = 30
----------------------------
(12.8/64)^2 (9.6/32)
What am I doing wrong? My book says the correct answer is 15. thanks.