Well I just looked up the first definition on Wikipedia:
Partial pressure is the pressure which the gas would have if it alone occupied the volume.
So it is probably the number of moles you would expect to find in 100 cm3 of air. I am not actually quite sure; this was only a suggestion.
ok: partial pressure's definition is right, but a bit troublesome formulated.
Say if you have 1 mol gas A and 2 mol gas B in a volume V at 3 atm, then the partial pressure of A would be 1 atm, because if the same amount of A as in that mixture (1/3 of the total moles present) would occupy the same volume (V) as that original mixture, it would have a pressure of 1/3 * 3 = 1 atm.
A useful formula to know for this question is that 1 mol of any gas occupies 24 dm3 of space.
Only at standard temperature and pressure.
However, for this question as originally posted by steve, the gaslaw is not needed, only the molar weights of the gases.