Deduce a structure consistant with the following data
C = 58.38%, H = 9.80% (C:H = 1:2)
(EI) m/z (abundance %): 207 (10), 205 (30), 204 (12), 192 (15), 190 (45), 170 (10), 164 (11), 162 (33), 157 (11), 156 (100)
(207:205 = 1:3, Cl is existed, 205 imply at least one N, 205 - 156 = 49 imply -CH2Cl fragmentation. The overall formula is C10H20NOCl)
IR (cm-1) : 2900, 1650
1H NMR (CDCl3):
1. 0.9 (6H,d)
2. 1.0 (6H,d)
3. 1.1 (3H,d)
4. 2.3 (1H,m)
5. 2.5 (2H,m)
6. 3.5 (2H, bd)
What I predict is:
(3)
CH3 CH3 O
l l ll
(H3C)2 - N - CH2 - C - C - C - CH2Cl
l l
CH3 H
(2) (5) (1) (4) (6)
Does my prediction have problems?