I was taught before that the stability affects the rate of the reaction of alkanes towards chlorination.
That is, as tertiary carbocations are more stable than secondary carbocations and primary carbocations, the rate towards chlorination is: Tertiary > Secondary >Primary.
You're not dealing with cations here! Alkanes are very unreactive.
Your general trend for cations still holds for radicals, but this does not mean that you will necessarily get more chlorinated product from a 3° radical than a 1° radical.
I've actually worked an example before where it's the exact opposite.
Look up the
reactivity-selectivity principle.
Chlorination is only good for molecules that have only one or two different kinds of carbon, i.e. cyclohexane. Each carbon is the same.
Depending on the rate of alkyl radical formation, from the reaction of a chlorine radical with a 3°, 2°, or 1° position, as well as the probability of hydrogen removal (i.e. how many hydrogens are at that position), you will get varying yields of monochlorinated product.
Bromination, however, is selective, so the formation of a 3° is much lower energy than for 1°.
The relative rates of alkyl radical formation are so different at a given temperature for bromination and chlorination, and that's the main reason why bromination gives you preferentially more product from the most stable radical—thus bromination is said to be
selective—whereas chlorination can give you varying yields from 1°, 2°, or 3° radicals—thus chlorination is said to be
reactive.