Alright, i've got this problem here which i'm having trouble understanding:
Liquid methanol is poured into a 500ml bottle then ignited by a spark between electrodes
For the equation 2CH3OH + 3O2 ---> 2CO2 + 4H2O
Calculate the number of moles of oxygen and methanol in a 500 mililiter bottle and identify the limiting reagent for the combustion reaction in the bottle. (The vapor pressure of methanol at 25 degrees Celsius is is 125 mmHg. Assume that air is 20% oxygen,the atmospheric pressure is 760 mmHg and the temperature is 25 degrees Celsius).
I know how to find the limiting reagent. However, my problem is finding the number of moles of each in the given situation. For the methanol, it seems like I can just divide the given mass by the molar mass to find the amount of moles. The amount of oxygen would of course be 3/2 that amount. Can someone explain to me why my teacher included the vapor pressure of methanol, the percent of oxygen in air, the current pressure, and the current temperature? What role does this play in my calculations. It seems like i can make those calculations without it.