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Topic: Theoretical neutralization capacity of antacids  (Read 9282 times)

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Offline beestree

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Theoretical neutralization capacity of antacids
« on: April 28, 2007, 01:55:44 PM »
Hello!!
I'm hoping to get some help with this lab problem of mine.  For this lab experiment, we first standardized a solution of 0.2 M HCL, and one of 0.2 M of NaOH...than used theses solutions to analyze the neutralizing power of three antacids.....Tums, Maalox, and Rolaids. 

All of the calculations have been no problem for me to figure out, until this one..

Problem:   Calculate the theoretical neutralization capacity of each of your experiments, based on the information on the labels of the three antacids. 

I have been driving myself crazy trying to figure out where to begin!!!  I have all of the calculations done to this point.....such as...the molarity of the solutions, volume of HCl solution neutralized by each antacid, and volume of stomach acid neutralized by 2 tablets or tsp of each antacid.

Any help/suggestions on how to go about this problem would be greatly appreciated!!!
Thanks very much.
Beestree.

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Re: Theoretical neutralization capacity of antacids
« Reply #1 on: April 28, 2007, 02:27:32 PM »
Look at the list of components on the labels. Which substances present should react with HCl? How much of these substances is present in each tablet?
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Offline beestree

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Re: Theoretical neutralization capacity of antacids
« Reply #2 on: April 29, 2007, 12:42:36 AM »
Hi,
Thanks for the help.

I'm not very confident that this is the correct answer but here is what I came up with.

Rolaids contains...550 mg of CaCO3, and 110 mg of Mg(OH)2.

soooo....

550 mg CaCO3(0.001 g/1 mg)(1 mol CaCO3/100.08 g CaCO3)(2 mol HCl/1 mol CaCO3) = 5.49 x 10-3 M HCl

110 mg Mg(OH)2(0.001 g/1 mg)(1mol Mg(OH)2/57.3 g Mg(OH)2)(2 mol HCl/1 mol Mg(OH)2) = 3.84 x 10-3 M HCl

total of 9.33 x 10-3 M HCl neutralized

Does this look correct??
Thanks very much.

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Re: Theoretical neutralization capacity of antacids
« Reply #3 on: April 29, 2007, 04:59:07 AM »
Not checking math details - that's the correct track :)
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