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Topic: Need help calculating pH, [OH][H]  (Read 4184 times)

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Offline cyberdx16

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Need help calculating pH, [OH][H]
« on: May 15, 2007, 06:09:20 PM »
heres the question, Calculate the pH [H], [OH] for a slution that contains 2.75g of Ba(OH)2 in a 2.5L solustion of water.

so far i know the Molarity is 6.4e-3, and i know that Ba(OH)2 is a weak base so it will not completely dissociate in H20. Also what is the balanced equ for this reaction?

Offline Borek

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Re: Need help calculating pH, [OH][H]
« Reply #1 on: May 15, 2007, 06:41:48 PM »
Ba(OH)2 is a strong base.
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Offline cyberdx16

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Re: Need help calculating pH, [OH][H]
« Reply #2 on: May 15, 2007, 07:29:27 PM »
Ba(OH)2 is a strong base.

it is among the few 2A hydroxides that are not strong bases

Offline Borek

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Re: Need help calculating pH, [OH][H]
« Reply #3 on: May 16, 2007, 02:59:17 AM »
1st, please check this page for HaOH/KOH strength explanation:

http://www.chembuddy.com/?left=FAQ

Same book lists stability constant for BaOH+ as 100.6 - it translates to pKb = 0.6. Second stability constant is not listed, which most likely means that it is much smaller (read: base is much stronger). pKb = 0.6 is a border case - not as strong as - say - KOH, but hardly weak. As Ba(OH)2 is weakly soluble it is usually not concentrated enough to be not fully dissociated. In your case it is dissociated in over 97%.

Your molarity is OK, you may safely assume 100% dissociation, reaction is simple dissociation.
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