A 78.5g iron object is placed in an oxygenated tank of 1.00 mol/L hydrochloric acid. What volume of oxygen at SATP would react to completely consume the iron object?
Okay so you nos I got to put down a formula down that is run into trouble you know so:
oxygenated tank = O2
hydrochloric acid= HCl
Iron= fe3
right?
okay so:
Fe3+ HClO2 --> this is were I am not sure??
help
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