Ok, im trying to find the equivalent weight of H+ for the Benzoic acid (2C6H5COOH), this is the reaction formula:
2C6H5COOH + Ca(OH)2 2 H2O +Ca(C6H5COO)2
This is the math Ive done:
(122.23g)(2)= 244.46 g/mol
mol
244.46 (1 mol H+) = 20.37 g/equiv.
12 mol H+ 1 equiv.
but for some reason this is not the correct answer... need a bit o' help, thanks
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Topic: Equivalent weight of acid (Read 7285 times)