Hello I am having a project in an organic synthesis course were im making 3-borpinacolpyrrol from pyrrol, I think I have most of the mechanism figured out but I would appreciate if somebody could take a look and see if im on the right track or if im completely lost
. Is my reaction to simplified...
The project is two steps were im in the first do remove an H wit t-BuLi on the pyrrol and put on a TIPS group (-Si(iPr)
3)so that when I use diboris-pinacolat it will substitute in 3-posision instead of in 2-position. This is going to be used later in an suzuki cross coupling reaction.
I think that the mechanism is proceeding like this:
The free elctrons on nitrogen will go into the ring and the double binding in the ring will connect with half of the pin
2b
2 and give the product 3-borpinacolpyrrol(see picture 2).
Does anybody have any idea in what way the iridium catalysator is helping the reaction.
Im putting along two pictures, the first showing the reaction while the last shows how I think the reaction proceeds. Any help would be appreciated.
If anybody is interrested in the original litterature that is:
Tetrahedron Letters 43 (2002) 5649-5651. Iridium-catalysed
[img=http://img503.imageshack.us/img503/4756/bildefq6.th.png][img=http://img147.imageshack.us/img147/9806/bilde2oq9.th.png]