[username*]

For each of the following four sets of conditions, enter the formula of the simple ionic compound that could form from the elements X and Z. Give the cationic element first and the anionic element second.
e.g. X3Z5 (if X is the cation) -- subscripts are inferred.
(Coefficients of "1" are omitted -- as in NaCl)


X has 4 valence electrons and Z has 2 valence electrons:
1pts

X has 6 valence electrons and Z has 2 valence electrons:
1pts
Tries 0/10

X has 7 valence electrons and Z has 2 valence electrons:
1pts
Tries 0/10

X has 6 valence electrons and Z has 1 valence electron:
1pts
Tries 0/10

I tried reading the text, and I've guessed a few times to no avail=( Help is appreciated!

[AWK]

THis is rather odd test, eg:
sulfur has 6 valence electrons and oxygen has 6 valence electrons. How can you decide which atom is a donor of electrons, and wich is an acceptor of electrons without knowledge on electronegativities of these elements.

[Yggdrasil]

Try comparing to real elements with that number of valence electrons.  (For example in the second problem, oxygen has six valence electrons and magnesium has two valence electrons.)