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Topic: balancing redox reaction  (Read 6480 times)

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Offline dipndots

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balancing redox reaction
« on: October 02, 2007, 11:54:12 PM »
I tried to balance this equation by doing the half-equations, but i only learned how to balance simple ones, and this one is not simple.



The following reaction occurs in basic solution. Balance it by adding only OH- or H2O.

MnO4-(aq) + NO2-(aq) --> MnO2(s) + NO3-(aq)

Offline Padfoot

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Re: balancing redox reaction
« Reply #1 on: October 03, 2007, 01:20:56 AM »
Treat as if were in an acidic environment initially.  When finished, add identical amounts of OH- to reactants and products to remove H+.

Offline AWK

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Re: balancing redox reaction
« Reply #2 on: October 03, 2007, 01:32:00 AM »
This reaction:
MnO4-(aq) + NO2-(aq) --> MnO2(s) + NO3-(aq)
goes in neutral conditions (neutral means water on the left side (or nothing more)
MnO4-(aq) + NO2-(aq) + H2O--> MnO2(s) + NO3-(aq) + OH-
AWK

Offline Padfoot

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Re: balancing redox reaction
« Reply #3 on: October 03, 2007, 02:28:36 AM »
MnO4-(aq) + NO2-(aq) + H2O--> MnO2(s) + NO3-(aq) + OH-
[/quote]

AWK, this reaction doesn't seem to balance, I think it is more complex. 
Using half equations I get:

2MnO4- + 3NO2- + 5H20 → 3NO3- + 2MnO2 + 4H2O + 2OH-

Correct me if I'm wrong though.

Offline Borek

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Re: balancing redox reaction
« Reply #4 on: October 03, 2007, 03:38:07 AM »
Treat as if were in an acidic environment initially.  When finished, add identical amounts of OH- to reactants and products to remove H+.

It works for you, which doesn't mean it is optimal.

Quote
MnO4-(aq) + NO2-(aq) + H2O--> MnO2(s) + NO3-(aq) + OH-

AWK, this reaction doesn't seem to balance, I think it is more complex. 
Using half equations I get:

2MnO4- + 3NO2- + 5H20 → 3NO3- + 2MnO2 + 4H2O + 2OH-

Correct me if I'm wrong though.

Correcting: you are wrong. This reaction can be balanced ;)

In fact you already did it - just remove excess water.

In the future - don't hijack threads, you have stripped dipndots from a chance to do his/her homework and to learn anything.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Padfoot

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Re: balancing redox reaction
« Reply #5 on: October 03, 2007, 05:52:41 AM »
Quote
In the future - don't hijack threads, you have stripped dipndots from a chance to do his/her homework and to learn anything.

Sorry and noted, but didn't AWK attempt to do this as well in this very thread??

Offline Borek

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Re: balancing redox reaction
« Reply #6 on: October 03, 2007, 09:11:38 AM »
Quote
In the future - don't hijack threads, you have stripped dipndots from a chance to do his/her homework and to learn anything.

Sorry and noted, but didn't AWK attempt to do this as well in this very thread??

I don't think so - he just hinted how to use water and OH- to balance oxygen.
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Offline AWK

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Re: balancing redox reaction
« Reply #7 on: October 03, 2007, 09:13:34 AM »
Sorry and noted, but didn't AWK attempt to do this as well in this very thread??

I give you direction of solving your problem (unbalanced reaction).
AWK

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