Given that Sm = 29.79 JK-1mol-1 for bimuth at 100K and
the following tabulated heat capacities data, compute the standard molar entropy of bismuth at 200K.
T/K 100 120 140 150 160 180 200
Cp,m/JK-1mol-1 23.00 23.74 24.25 24.44 24.61 24.89 25.11
Compare the value to the value that would be obtained by taking the heat capacity to be constant at 24.44 JK-1mol-1 over this range.
This is my attempted answers:
S(200 K) = 29.79 + 24.44 ln 2 = 46.73 JK-1mol-1
but how can I get the another S (200 K) for the tabulated datas? Thank you!