Ok I've done the question and want to check if I am on track or not.
Q. A 0.006141 mol sample of an organic compound was burned in oxygen in a bomb calorimeter. THe temperature of the calorimeter increased from 23.1 degress to 27.1 degrees. If the heat capacity of the calorimeter is 4.90 kJ(degrees)-1, then what is the constant volume heat of combustion of this compound, in kJ/mol[Remember to include a "+" or "-" sign in your answer, as appropriate)
Have your answer with three significant figures.
A. Here's what I've done,
since delta T = q comb x moles / heat capacity
(27.1 - 23.1) = q comb x 0.006141/ 4.9
q comb = 3191.828 kJ/mol
but my answer is not with three signi. figures?? and where am i supposed to include the + or - sign??
I am confused. HELP PLEASEEEE!!!!