I had two questions that I answered but I don't know if they are right.
First, "Before the public became serious about pollution, it was common to improve the performance of gasoline by the addition of lead compounds. A particular 100-octane aviation gasoline used 1.00 cm3 of tetraethyl lead, (C2H5)4Pb, of density 1.66 g/cm3, per liter of product. How many grams of ethyl chloride are needed to make enough tetraethyl lead for 1.00 L of gasoline?"
4(C2H5Cl) + 4(NaPb) --> (C2H5)4Pb + 4NaCl + 3Pb
g? 1.66g
To find how many grams of (C2H5)4Pb I needed, i multiplied 1.00 cm3 with 1.66 g/cm3 to get 1.66 g/l (C2H5)4Pb.
Then I divided 1.66g (C2H5)4Pb by 323 g/mol (C2H5)4Pb to get .005 mol (C2H5)4Pb.
Then I multiplied .005 mol by 4 because of the 4:1 ratio to get .02 mol C2H5Cl
And last I multiplied .02 mol by 64.6 g/mol to get 1.29g C2H5Cl
Is that right?
Second, I had to write several lewis structures but there are a few that I am not sure if I did right either.
a) C2HCL H-C triple bond C-Cl
b) C2H6O I had originally put H H but when I looked online, it had the O in
H-C-C-O-H between the carbons or the OH on top of
H H one of the carbons instead of on the
outside. Does it matter?
c) C2H4O I put H H but online, I saw it with the double bond between the
C=C-O-H C and the O like H H
H H-C-C=O
H
Is the way I drew it wrong and how was I supposed to know that the double
bond is between the C and the O and not between the carbons?