Having problems with the structure and preparations of bisthioureacopper(II) sulfate & tristhioureacopper(I) sulfate
I expect tris(tu)copper(I) to be octahedral but is the copper(II) complex tetrahedral or square planar?
also to prepare tris(tu)copper(I)sulfate from copper(II)sulfate what would the correct reaction pathway be?
CuSO4 + 2tu --> [Cu(tu)2]SO4
[Cu(tu)2]SO4 + H2SO4 + tu --> [Cu(tu)3]SO4 ...
is the sulfuric acid acting as a reducing agent here? or is there something i'm missing?
please help can't find much about these compounds!!