Hi
I'm a new member I'm not sure how this works but i have a prelab and I'm not sure if my answer is right so it would be awesome if someone could tell me whether my solution is correct or not
A compound containing only boron, nitrogen and hydrogen was found to be 40.3% B, 52.2% N, and 7.5% H by mass. If 3.301g of this compound is produced freezes at 1.30ºC. If Kg for benzene is 5.12ºC/m and the freezing point of pure benzene is 5.48ºC, What is the molecular weight of this compound?
deltaTf = KfXm
(5.48ºC-1.30ºC) = 5.12ºC/m x m
m= 4.18ºC / 5.12ºC/m
m= 0.816
m= mole of solute(unknown) / kg Solvent(benzene)
mole solute= 0.816x0.05kg
mole of solute= 0.0408 mole
molar mass= g solute / mole solute
molar mass= 12.00g/0.0408 mole
molar mass= 294.12g/mole