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Topic: Chemical Equilibrium Problem  (Read 4627 times)

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Offline planke

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Chemical Equilibrium Problem
« on: November 10, 2007, 05:42:49 PM »
Can someone please help me with this problem?

The following reaction has Kp = 109 atm-1 at 258°C.
2 NO(g) + Br2(g)  (half arrows) 2 NOBr(g)
                       
If the equilibrium partial pressure of Br2 is 0.0173 atm and the equilibrium partial pressure of NOBr is 0.0630 atm, calculate the partial pressure of NO at equilibrium.
______atm

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Offline Padfoot

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Re: Chemical Equilibrium Problem
« Reply #1 on: November 10, 2007, 06:26:24 PM »
Quote from: planke on November 10, 2007, 05:42:49 PM
______atm
Thankyou for leaving the space ;)

This question is just math.  Write down eqn for Kp using the info given and you can simply solve for partial pressure of NO.

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Offline planke

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Re: Chemical Equilibrium Problem
« Reply #2 on: November 10, 2007, 06:41:24 PM »
What does 109atm^-1 mean?
109 x 10^-1? I have no clue.
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Offline LQ43

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Re: Chemical Equilibrium Problem
« Reply #3 on: November 10, 2007, 07:03:34 PM »
it means

109
atm

whenever a unit has a negative exponent eg. mol^-1, K^-1, it means that it is in the denominator
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