[SpontaneousRxn]

Hello everyone!
I just have a really quick question.  For my general chemistry class, we were asked to synthesize calcium fluorite using calcite, villaumite and hydrochloric acid only.  I got my reactions to get to the calcium fluorite part.  My question is, what kind of reactions are they?
These are my rxns:
CaCo3 + 2HCl -> CaCl2 + CO2 + H2O

CaCl2 + 2NaF -> CaF2 + 2NaCl

Is it precipitate? Acid base???
I am just clueless....

Thanks for any input 

[shelanachium]

The first reaction is acid/base, or more specifically decomposition of a carbonate by an acid. Carbonic acid H2CO3 is weak, so readily displaced by the much stronger acid HCl; it is also spontaneously unstable, decomposing to water and carbon dioxide, which escapes as gas:

CaCO3 + 2HCl -> CaCl2 + [H2CO3]

[H2CO3] -> H2O + CO2 (gas)

The second reaction is a 'double decomposition' which occurs when a solution contains ions any of which can combine to form a salt of low solubility. NaF and CaCl2 are both soluble in water, NaF giving Na+ and F- ions, and CaCl2 gives Ca2+ and F- ions. When the solutions are mixed, the Ca2+ and F- ions form insoluble CaF2 as a precipitate. The Na+ and Cl- ions remain in solution as sodium chloride is soluble in water.

[shelanachium]

Woops. Missed a typo. CaCl2 of course gives Ca2+ and Cl- ions not F-!

[SpontaneousRxn]

thank you so much!!!