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Topic: word problem  (Read 3733 times)

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Offline blindsided

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word problem
« on: November 15, 2007, 08:56:56 PM »
What is the molarity of a solution that contains 12.5grams of NaHCO3 in 350mL solution?

so far I have:

12.5gNaHCO3 X  1mol/84gNaHCO3= .149molNaHCO3


I think next i should do:


.149mol/.35L= .43M NaHCO3

Not sure though.
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Offline ARGOS++

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Re: word problem
« Reply #1 on: November 15, 2007, 09:16:09 PM »
Dear Blindsided;


Yes!  OK. - Please go ahead.  (MolaRity = mol / Liter).

Good Luck!
                   ARGOS++
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Offline blindsided

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Re: word problem
« Reply #2 on: November 15, 2007, 11:43:23 PM »
ok. so: .43M NaHCO3/L is correct?

thanks bud
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Offline ARGOS++

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Re: word problem
« Reply #3 on: November 16, 2007, 12:33:33 PM »

Dear Blindsided;


Once again: Yes!  - A little bit more exact: 0.425 mol NaHCO3 / Liter.

Good Luck!
                   ARGOS++
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