[Toxage]

 I am confused on my Chemistry assignment and was wondering if someone could help me. I am confused on how to do number 2.

Lab Data

Mass of Calorimeter and Water 256.932g
Temperature of Calorimeter and Water 42.9 celsius
Mass of Calorimter and water and melted ice 266.045g
Temperature of Calorimeter and Water and Melted ice 36.5 celsius


1. Calculate the mass , m of (melted) ice used.

2. Using your answer from #1, calculate the heat, q, absorbed by the water from the ice. (Assume the intial temperature of the ice was 0.0 degrees celsius)


1. 266.045 - 256.932=9.113g

2. Q=M*C*Delta T

Q= 9.113*0.5*

I am unsure of what the Delta T would be.... Would it just be 42.9-36.5?

[enahs]

I am unsure of what the Delta T would be.... Would it just be 42.9-36.5?

No.

What is the initial temperature of the ice? What is the final?

[Toxage]

So would it be 36.5-0.0=36.5 as the delta T?

[enahs]

This is actually a poor question; I wish I read it more carefully before my first response.

The water does not absorb any heat from the ice. It in fact gives some of it's energy in the form of heat to the ice to cause the ice to melt. If it absorbed energy in the form of heat it's temperature would increase, but the temperature decreases. Obviously the q will be negative, which is valid, but that is not absorption.

What you can calculate from your known amount of ice that melted is how much energy the water had to supply to achieve that (look in your notes, or book or internet for Enthalpy of fusion).

[Toxage]

Our lab is titled - The Heat Fusion Of Water, we are calculating the heat fusion of water so we can't use it.

[enahs]

Ohh well ok, that makes a little more sense then.
Do you not know the mass of the water though?

[Toxage]

The mass of the water is 200 grams.

[enahs]

Ok,
So you know the specific heat of Water, the mass of water, and the change in temperature of water.
You know the mass of the ice. You know everything but the enthalpy of fusion.

Q₁+Q₂=0 or Q₁=-Q₂

m_water * C_water * ΔT_water = -m_ice * Enthalphy of fusion.

What is the Enthalpy of fusion?

[Toxage]

200*1.0*6.4=9.113X
1280=9.113X
140 Something

That doesn't seem right though, we never learned any of the things you said above..

I think 2 is meant to say released instead of absorbed  in which case I think I would just calculate the heat given off by the water and then the heat given off by the ice and subtract them but I am kinda guessing here.

[enahs]

http://www.saskschools.ca/curr_content/chem30/modules/module3/lesson4/enthalice.htm