[Youngstudent]

I am trying to do this question in my book that reads:
A 25.0 mL sample of sulfuric acid is completely neutralized by adding 32.8 mL of 0.116 mol/L ammonia solution. Ammonium sulfate, (NH4)2SO4, and water are formed. What is the concentration of the sulfuric acid?
And here I am trying to balance the equation for an hour until I finally gave up? So is that an error in the question or is my brain just not working?

[Yggdrasil]

Ammonia is basic because it reacts with water to create hydroxide ions.

NH_{3 (l)} + H₂O_(aq) --> NH₄⁺_(aq) + OH^-_(aq)

I hope this helps.

[IITian]

Further,

2NH₄OH + H₂SO₄=(NH₄)₂SO₄+2H₂O

[Borek]

You can edit your posts - just click on Modify

[IITian]

thanks 

[Atome]

Ammonia is basic because it reacts with water to create hydroxide ions.

NH_{3 (l)} + H₂O_(aq) --> NH₄⁺_(aq) + OH^-_(aq)

I hope this helps.

Hello there,

For this chemical equation, where would there be water with which ammonia would react to form ammonium hydroxide (NH₄OH)? Would it be the water in the aqueous ammonia solution?

Thanks.

[Arkcon]

Yes, we kinda all assumed it was a aqueous reaction, because the ammonia was given as a concentration, molarity, and not as a gas or a liquefied ammonia.  Basic high school chemistry tend to gloss over reaction in liquid ammonia, or other liquefied polar gases, exciting though they are.

[Atome]

Thanks for your reply, Arkcon.

When I performed the stoichiometry calculations, I did not get the textbook's answer.

Since the reactants are H₂SO₄ + 2NH₄OH, the mole-mole ratio is 1:2.

NH₄OH in mols = 0.0328 L x 0.116 M

                                   = 0.0380 mol

Therefore:

[H₂SO₄] = 0.0190 mol/0.0250 L = 0.760 M

The textbook gives an answer of 0.304 M.

[Borek]

No matter what's in textbook, 0.07608M is correct. Or 0.0761M to use 3 sigfigs.

Edit: typo (781 instead of 761) corrected.

See how easy it is to solve such a problem with the EBAS, stoichiometry calculator: https://www.facebook.com/watch/?v=522861421884614

[Atome]

All right. Thanks for your help Borek!