Hi guys, can someone tell me if I did the ff. setup correctly?
How many grams of water are liberated by the complete decomposition of 100g of copper (II) sulfate pentahydrate?
CuSO4.5H2O ----> CuSO4 + 5H2O
100g CuSO4.5H2O (1 mol CuSO4.5H2O / 250g CuSO4.5H2O) (5 mol H2O / 1 mol CuSO4.5H2O) (90g H2O / 1 mol H2O)
Thanks!