So, i basically have trouble getting this concept,
but I'll just ask you guys one of my homework questions and if you guys could help out, I'd really appreciate.
Question: Which of the following cells would produce a spontaneous reaction? Justify each answer, using cell potential:
C(s) | Cr(NO3)2 (aq) | C(s)
What I have so far:
The things involved in this cell are: NO3[1-], Cr[2+], and water C is inert, so no effect
I have that the Cr[2+] is the Strongest Oxidizing Agent (using a table in my textbook) therefore it will under go reduction
Cr[2+] + 2e -----> Cr(s) (E = -0.91)
I found that water is the Strongest Reducing Agent, therefore it will oxidize
2H20 -----> 4e + 4H +O2 (E = 1.23)
Now since i have my half reactions, i can calculate the change in E
E(cathode) - E(anode)
= -0.91 - 1.23
= -2.14
therefore, this is not spontaneous because energy is needed to be put in.
the problem is, the answer in the back of the textbook says -0.50V...