consider the decomposition of liquid benzene, C6h6(l), to gaseous acetylene, C2H2(g)
1/3C6H6(l)---> C2H2(g) delta H= +210kJ
a. what is the enthalpy change for the reverse reaction?
b. what is the delta h for the decomposition of 1 mole of benzene to acetylene?
c. which is more likely to be thermodynamically favored, the forward or reverse reactions?
d. if C6H6(g) were consumed instead of C6H6(l) would you expect the magnitude of delta h to increase, decrease, or stay the same? explain.
for the reverse reaction, is the formula c2h2---> 1/3 c6h6?
and wouldn't the delta h just be negated?