[chay722]

Two different oxides of manganese are compared:
1. black /63.19% by mass manganese/ 36.81% by mass oxygen
2. dark greeen/77.50% by mass manganese/ 22.50% by mass oxygen

Which pair of values when substituted for X and Y in the fraction below gives a result that illustrates the Law of Multiple Proportions?

(63.19/X) / (77.50/Y)

a. X-54.94 y=16
b. x=54.94 y=54.94
c. x=16 y=16
d. x=22.50 y=36.81
e. x=36.81, y=22.50

I think the answer is choice e because when you calculate it out it comes to 1/2 and all the other choices give random numbers you can't really round up but I don't see how this would illustrate the law of multiple proportions if it isn't even a whole number.

[Kryolith]

all the other choices give random numbers

This is no question of trial and error

http://chemistry.about.com/library/weekly/aa012903a.htm

[chay722]

Yeah I've already seen that example, but thanks.

[Kryolith]

Well, your answer is correct, but you should be able to set up such equations without multiple choices. I am sure you can 

[chay722]

  Well, thank you.