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Topic: Nernst equation  (Read 6471 times)

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Offline THC

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Nernst equation
« on: January 26, 2008, 11:48:50 AM »
http://en.wikipedia.org/wiki/Nernst_Equation

What if I want to calculate E for T = 400 K?
I only know E^0 at 298 K... does it make a big difference if I use the E^0 at T = 298?

Offline Kryolith

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Re: Nernst equation
« Reply #1 on: January 26, 2008, 12:35:31 PM »
The first formula has the term RT/zF with T=temperature. So what's the problem?

Offline Borek

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Re: Nernst equation
« Reply #2 on: January 26, 2008, 12:38:47 PM »
The first formula has the term RT/zF with T=temperature. So what's the problem?

Phase transition.
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Offline Yggdrasil

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Re: Nernst equation
« Reply #3 on: January 26, 2008, 01:07:53 PM »
Eo will change with temperature, so you would have to find the value of Eo at 400K.

Offline THC

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Re: Nernst equation
« Reply #4 on: January 26, 2008, 07:13:53 PM »
The first formula has the term RT/zF with T=temperature. So what's the problem?

Phase transition.

That too, but consider a reaction A (aq) + B (s) -> C (s) + D (aq), where all the reactants and products are in there standard state. Then what if T= 400 K? ln 1 = 0, so E = E0 anyway, even though the temperature is wrong.

Eo will change with temperature, so you would have to find the value of Eo at 400K.

My conclusion too, but different values of E0 are rarely provided. Is it safe to assume that E is independent of T at relatively small derivations from T = 298 K?

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