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Topic: Thermochem  (Read 3961 times)

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Offline scrum

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Thermochem
« on: January 29, 2008, 11:56:22 PM »
One mole of an ideal gas with a volume of 2 L and a pressure of 3 atm is allowed to expand isothermally into an evacuated bulb to give it a total volume of 4 L. Calculate w and q. Also, calculate qrev for this change of state.

I got DeltaV = 2L, so i figured that w = - P Delta V

-3 * 2 = -6 L atm * 101.3 and got -607 J to be w

this is wrong, but i don't know how to do the others so i'm stuck. a lot of my formulas want a change in temperature so i'm unsure of what to do.

Offline Valdorod

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Re: Thermochem
« Reply #1 on: January 30, 2008, 01:28:55 PM »
I may be way off base here, but it seems like a trick question

isn't work = 0 when a gas expands against a vacuum (evacuated bulb)?

and if the system is isothermal shouldn't q also be 0 since there was no change in temperature.?

Valdo

Offline enahs

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Re: Thermochem
« Reply #2 on: January 30, 2008, 08:13:02 PM »
Yes Valdo.

It is not a trick question. It is the beauty of ideal gases and simplifying systems with terms like isothermal. Stuff stops dropping out and making calculations easy, yet you still get a good approximation of the system.


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