[pmlam]

Hi, I am struggling on a chem question:

The rate law reaction 2NO2(g) ----> 2NO(g) + O2(g) is
Rate = k[NO2]2

By what factor does the rate change if the concentration of NO2 goes from 0.19M to 0.44M?

I don't know how to solve because k nor delta t is given.... @_@

thanks!

[enahs]

http://www.chm.davidson.edu/ChemistryApplets/kinetics/DifferentialRateLaws.html

It is second order with respect to NO₂, so you tell me?

[pmlam]

1/[NO2]-1/[NO2]o=kt.....am I trying to solve for the rate change..

[Sev]

You have to find the factor by which the rate changes, i.e: R₂/R₁.

R= k[NO₂]² - you know [NO₂], k cancels.

[pmlam]

so rate = [.19M - .44M]^2?

[Sev]

Not quite.

R₁= 0.19²k, R₂= 0.44²k

So R₂/R₁ = ?

[pmlam]

Oh! okay! geeze...i feel so stupid.. ><

[pmlam]

i get it now. thank you thank you!!