[THC]

Write the reaction mechanism between (CH3)3N and CH3Br.


Well, (CH3)3N is an nucleophile reagent, and Br- must be the leaving group. Since CH3Br is primary, it's probably a SN2 reaction, right? But I can't quite figure out the products. Is it (CH3)3N(+)CH3 + Br-?

[Rico]

Hey THC

SN2 reaction is correct and yes the product is the quaternary ammonium bromide salt.

Rico

[THC]

Hey THC

SN2 reaction is correct and yes the product is the quaternary ammonium bromide salt.

Rico

Thanks for your answer. What is more stable, the reactant or products? I can't imagine (N(CH3)4)+ is that stable?

[russellm72]

Tetraalkyl ammonium halides are generally stable and used a lot...

Remember this is a solid whereas the two reagents are volatile. Not saying that makes them unstable but maybe that is what they mean in your question.

R

[THC]

Tetraalkyl ammonium halides are generally stable and used a lot...

Remember this is a solid whereas the two reagents are volatile. Not saying that makes them unstable but maybe that is what they mean in your question.

R

Isn't it dissolved in the solvent since it's an ion (i.e. not (s), but (aq))?