Hello everyone. Im new to this forum and im in my first year of college and i have not studied chemistry before. I have a problem with my chemistry lab report. The experiment (Analysis of an acid lavatory cleaner) was to titrate 25ml of NaHSO4 against 0.1M of NaOH. After i did three titrations, the average volume of NaOH used was 29.167mls. One of the questions was to work out the % of active ingredient, NaHSO4, in the sample. I have calculated the number of moles of NaHSO4 which is 0.0029167, im just not sure how to work out the percentage. Please help