Determine the molarity of the saturated KNO3 solution at 25 Celcius.
I used a graph to determine that 40 grams of KNO3 can dissolve in 100 grams water at 25 Celcius.
40 Grams * 1 Mol
------ = 0.396 Moles --> 0.4 Moles (Sig Figs)
101 Grams
Molarity = Moles Solute
-------------
Liters Solvent
X = 0.4
-----
Y
The problem is I can't use the molarity equation because the solvent is in grams, not liters. I could determine the molality, but there is no way to change molality to molarity. I know of no way to change grams to liters.