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Topic: HCl + Mg ??  (Read 5773 times)

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Offline GreyMan

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HCl + Mg ??
« on: March 12, 2008, 06:01:53 PM »
I'm having trouble understanding what seems to be a simple stoichiometry problem. I reacted 15 ml of HCl with 0.1 g of Mg to get MgCl2 and H2. I need to calculate the amount of H2 in ml produced.

When I try to do the work, I just don't understand what 1 mol of HCl is. How do I take 15 ml of HCl and turn it into moles? Do I need to know the concentration of the HCl in the water to determine this or am I missing something else?

Thanks

Offline Arkcon

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Re: HCl + Mg ??
« Reply #1 on: March 12, 2008, 06:26:48 PM »
Yes, you will need some measure of the concentration of the HCl in solution, unless you were working with HCl gas.
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Offline GreyMan

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Re: HCl + Mg ??
« Reply #2 on: March 12, 2008, 06:39:56 PM »
I believe it was a 38% solution in water. Where do I go from here?

Offline Borek

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Re: HCl + Mg ??
« Reply #3 on: March 12, 2008, 07:10:00 PM »
If it was %, you will need density as well.

Not exact, but close...

http://www.chembuddy.com/?left=CASC&right=density_tables
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Offline GreyMan

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Re: HCl + Mg ??
« Reply #4 on: March 12, 2008, 07:19:57 PM »
So HCl is about about 1.2 g/mL at a 38% concentration. If there are 15 mL, that means there are 18 g of HCl. I'm confused. Now, how exactly do I find how many mL are in one mol of HCl?

Offline Borek

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Re: HCl + Mg ??
« Reply #5 on: March 12, 2008, 07:27:05 PM »
Now you calculate masss of HCl, then you convert mass to moles.
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Offline GreyMan

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Re: HCl + Mg ??
« Reply #6 on: March 12, 2008, 07:44:42 PM »
I'm really not sure how do to this. I'm pretty new to this. Can you explain this?

Offline Borek

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Re: HCl + Mg ??
« Reply #7 on: March 12, 2008, 07:49:59 PM »
HCl is 38% of 18 g.

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Offline Arkcon

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Re: HCl + Mg ??
« Reply #8 on: March 12, 2008, 08:07:27 PM »
Use the formula mass of HCl as a conversion factor from grams to moles.  That's published, or written on the bottle, just like the density is.  Or you can calculate it, from elemental mass.
« Last Edit: March 12, 2008, 09:43:49 PM by Arkcon »
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