Why was my answer incorrect?
Question:
Try this question to see if you can use standard enthalpies to determine the molar enthalpy for the reactions given. Your answer must be in kiloJoules and accurate to 0 decimal places unless specified.
Find the molar enthalpy of a reaction with:
Solid calcium oxide and liquid water producing solid calcium hydroxide.Answer accurate to 1 decimal place
My answer:
CaO(s) + H2O(l) produces Ca(OH)2
38.1 69.95 83.4
69.95 (J /(mol x k)) / 1000 = 0.06995
38.1 (J /(mol x k)) / 1000 =0.0381
83.4 (J /(mol x k)) / 1000 = 0.0834
∆H = ∑n∆H°f(prod.) - ∑n∆H°f(react.)
=.0834 - (.06995 + 0.0381)
= .0834 - 0.10805
= -0.02
= -0.0 kJ /mol