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Topic: Final Temperature  (Read 2816 times)

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Offline Marcus Soutlo

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Final Temperature
« on: March 22, 2008, 11:27:17 AM »
A 13.0 g block of iron at 95 degrees Celsius is dropped into 80.0 g of water at 15 degrees Celcius. What is the final temperature (degrees celsius) of the iron/water mixture?

Given
m = 13 g of Fe
m2 = 80 g of H2O
T1 = 95 degrees celsius
T2 = 10 degrees celsius
cFe = 0.444
cH2O = 0.418

QH2O - QFe
mH2OcH2O(Tf - TH2O)


Thats what I have so far what needs to be my next step?
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Offline Yggdrasil

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Re: Final Temperature
« Reply #1 on: March 22, 2008, 12:35:55 PM »
Remember that q = m c (Tfinal-Tinitial).

The amount of heat lost by the iron is equal to the amount of heat gained by the water.  Can you set up an equation to represent this mathematically, then solve for Tf?

[edit: fixing tags]
« Last Edit: March 22, 2008, 12:49:48 PM by Yggdrasil »
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Offline ARGOS++

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Re: Final Temperature
« Reply #2 on: March 22, 2008, 12:46:02 PM »

Dear Marcus Soutlo;

Have you already done a search on the Forums, there are several identical Questions already solved?
(It should always be the first on the Forums, after have tested other sources.)

Sorry! -  Yggdrasil.

Good Luck!
                    ARGOS++

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