Hi,
I am having trouble with this problem I think I have it right ,but id like for someone to double check my work. Onto the problem, Calculate the pOH of a 1.826 M aqueous solution of KOH at 25 degrees C.
I think I just take the -log of 1.826 and that is the anwser ,but I end up with -.26 , I dont think you can have a negative can you?
Thank you,