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Topic: Boric acid solution..(help)  (Read 4216 times)

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Offline karina

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Boric acid solution..(help)
« on: March 28, 2008, 09:08:35 AM »
i prepared a solution of boric(III) acid by dissolving 3.11g boric(III) acid and 3.73g potassium chloride in  distilled water, making up 250mL of solution in a voulmetric flask.

Can anyone help me find the molaritry of the boric(III)acid solution...

is it : 3.11/68.832 = 0.045 moles

(0.045 x 1000)/250 = 0.181 M  BORIC (iii) ACID..  ?..

is this how? and do i have the molar mass of the boric(III)acid right?
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Offline Borek

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Re: Boric acid solution..(help)
« Reply #1 on: March 28, 2008, 09:56:41 AM »
Molar mass is wrong, otherwise OK.
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Offline karina

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Re: Boric acid solution..(help)
« Reply #2 on: March 28, 2008, 12:01:15 PM »
thanks.. :) i found the molar mass... 8)
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Offline Borek

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Re: Boric acid solution..(help)
« Reply #3 on: March 28, 2008, 12:14:23 PM »
Instead of looking for - learn how to calculate. H3BO3 means 3 x molar mass of hydrogen, 1 x molar mass of boron, 3 x molar mass of oxygen. Elements molar masses available in every periodic table.
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