[luckycharm]

If air contains 21% mole oxgen and at 25 degrees celscius then Henry's Law constant for oxygen in water is 1.23 x 10^-4 mol/ L-Atm, find the solubility of oxygen in water;

a) at sea level and,
b) in the mountains where the air pressure is 0.90 atmosphere

what is the solubility of oxygen?

I am stuck at s = (1.23 x 10^-4 mol/ L - Atm)(.21)(1.0 atm) = 2.58 x 10^-5 mole/L


Thank you so much for your time!

[LQ43]

a) at sea level and,

what is the solubility of oxygen?

I am stuck at s = (1.23 x 10^-4 mol/ L - Atm)(.21)(1.0 atm) = 2.58 x 10^-5 mole/L

looks okay to me,

do the same calculation for the mountain but Ptotal is now 0.90 atm