[Winga]

When a solution mixture reacts to give a solid product, will the equilibrium shift completely to the product side?

If not, from which step that governs the reaction equilibrium?

[Organic_lover*]

To understand how a reaction of this type occur, you have to remember that:

-To occur the formation of the product, the system itself have to present a negative Gibbs free energy. The :delta: G it's a function that express the spontaneity of the reaction, in other words, if the reaction is energetically favorable or not.

So, assuming that we have the reagents (A and B )and mixing this two it's formed a product (C), we can determine if the reaction is occuring in differents times calculating* :delta: G/ :delta: t.

Considering the idea that the mechanism involved in a energetically favorable reaction may take differents steps (and some of this steps are yet studied by cientists), to tell which step governs the  equilibrium you have to talk about a specific reaction (and still would require a detailed study on the reaction in question).

In the equilibrium (you have to remember yourself) that the quantity of reagents and products are nearly constant. So, even in a heterogeneous reaction the equilibrium have the interconversion of C to A e B. The product will be obtained in the system if it's energy is lower than the energy of the reagents.

I hope this helps. If I told you something wrong someone will came here and answer your question better

Bye-bye o/

[orgopete]

When a solution mixture reacts to give a solid product, will the equilibrium shift completely to the product side?

If not, from which step that governs the reaction equilibrium?

That is the essence of the Finkelstein reaction (RCl + NaI  RI + NaCl(s)). Iodide is a good leaving group and the reverse reaction is possible. However, since sodium chloride is less soluble and precipitates, its low concentration in the solution drives the equilibrium toward the iodide.